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-z^2+2z=1
We move all terms to the left:
-z^2+2z-(1)=0
We add all the numbers together, and all the variables
-1z^2+2z-1=0
a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{-2}{-2}=1$
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